if formula question

Baek

I'm trying to make formula but it's not going well

IF ステータス = 承認済み THEN TRUE ELSE FALSE

how can i make this formula?

I_Approval Status.JPG I_Approval Status blue.JPG I_Approval Status error.JPG

I need your help... please help me

Accepted answers

Sai_Bharadwaj_Venati

Hey,

Don't know the language, but understood something

I guess formula should be like

IF name(List formatted line item) = "alert text" THEN TRUE ELSE FALSE or it can be

IF name(List formatted line item) = Line item [Remove name if it's Line item is list format] THEN TRUE ELSE FALSE

You can write formula little better => name(List formatted line item) = "alert text" [No need of use for IF Else condition in this case]

Thanks & Regards,

Sai Bharadwaj

https://www.linkedin.com/in/sai-bharadwaj-venati/

kevin.cho

Hi @Baek

You need to ensure you're comparing the same data types in your equality.

The line item ステータス is formatted as S_Status, so the right hand side of your equation "承認済み" needs to also be a list formatted line item or value.

If 承認済み is an item in S_Status, then it would need to be rewritten as:

ステータス = 'S_Status'.承認済み

As @Sai_Bharadwaj_Venati also said, rather than doing the

IF ステータス = 'S_Status'.承認済み THEN TRUE ELSE FALSE

You can just leave it as:

ステータス = 'S_Status'.承認済み

Since if this is TRUE, then it will return TRUE, and if it's false it will return FALSE.

All comments

Sai_Bharadwaj_Venati

Hey,

Don't know the language, but understood something

I guess formula should be like

IF name(List formatted line item) = "alert text" THEN TRUE ELSE FALSE or it can be

IF name(List formatted line item) = Line item [Remove name if it's Line item is list format] THEN TRUE ELSE FALSE

You can write formula little better => name(List formatted line item) = "alert text" [No need of use for IF Else condition in this case]

Thanks & Regards,

Sai Bharadwaj

https://www.linkedin.com/in/sai-bharadwaj-venati/

kevin.cho

Hi @Baek

You need to ensure you're comparing the same data types in your equality.

The line item ステータス is formatted as S_Status, so the right hand side of your equation "承認済み" needs to also be a list formatted line item or value.

If 承認済み is an item in S_Status, then it would need to be rewritten as:

ステータス = 'S_Status'.承認済み

As @Sai_Bharadwaj_Venati also said, rather than doing the

IF ステータス = 'S_Status'.承認済み THEN TRUE ELSE FALSE

You can just leave it as:

ステータス = 'S_Status'.承認済み

Since if this is TRUE, then it will return TRUE, and if it's false it will return FALSE.

ManjunathKN

Hi @Baek

you can code something like this

Name(ステータス)= "承認済み"

Thanks,
Manjunath

Baek

Hi,

Thank you for answer
it really helped!

Have a wonderful week ahead!

Baek

Hi,
Thank you for answer!
you are a genius.
Thanks for your help in solving this problem.
I will never forget what I learned.
Have a nice day!!!

Quick Links

Can you help?

Unanswered questions

XL3SetProperty to navigate
Hi everyone, I'm trying to use this function on specific members of my grid, as described in the documentation. In my example, the grid contains two row elements: ACTIF and PASSIF. The problem is that when I use this function, it affects all elements in the grid, whereas I only want it to apply to the specified member:…
Anaplan XL - Member Properties
Hi, Where are the member properties for lists defined in Anaplan XL? In the training documentation there is an example showing a property such as “Birth Date”, which appears to be a list-item attribute. That suggests you can create custom list properties from the Anaplan list. However, when I connect through Anaplan XL, I…
How to calculate the weight?...
Hi all I have a list of networks organized hierarchically on a list of entities, which is itself organized hierarchically on a list of divisions (organization). An entity can have several networks. I also have a list of product models, which is itself ranked with three higher levels: this “Models” L4 list is ranked at a…